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-2p^2+24p-54=0
a = -2; b = 24; c = -54;
Δ = b2-4ac
Δ = 242-4·(-2)·(-54)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12}{2*-2}=\frac{-36}{-4} =+9 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12}{2*-2}=\frac{-12}{-4} =+3 $
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